Like always, first determine the genotypes of the parents. We know that the bull has normal hocks so he must have an XN chromosome and, because he is male, the other sex chromosome must be what?
The female is a carrier for rabbit hock, meaning she does not exhibit the trait but has one of the recessive alleles. What is her genotype?
Now perform a punnett square, placing the gametes of one parent across the top and the gametes of the other parent down the side. You will not be able to use superscripts on this table so use XN, Xn, and Y in your notation.
Your punnett square should look similar to the one below. If it does not, review the material on gamete formation and how to set up the punnett square and try again.
Now count up how many of each genotype and phenotype you have in the male offspring and in the female offspring.
Return to the question page to select the correct answers.